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Two beads connected by a light inextensible string are placed over fixed vertical ring as shown in figure. If mass of each bead is 100 gms and all surface are frictionless if the tension (T) in the string just after the beads are released from the shown position, then find $T^{2} (i n N^{2})$ ? If it is $\frac{1}{x}$ . Find the value of x. $(g = 10 m / s^{2})$

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Detailed Solution

$m g - \frac{T}{\sqrt{2}} = m a$

$\frac{T}{\sqrt{2}} = m g a$

$T = \frac{m g}{\sqrt{2}}$

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