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Q.

Two blocks , each having a mass M, rest on frictionless floor surfaces as shown in the figure. If the pulleys are light and frictionless and M on the incline is allowed to move down, then the tension in the string will be

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a

$2 Mgsinθ$

b

$\frac{2}{3} Mgsinθ$

c

$\frac{Mgsinθ}{2}$

d

$\frac{3}{2} Mgsinθ$

answer is C.

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Detailed Solution

Acceleration of system, $a = \frac{Net pulling force}{Total mass}$

$= \frac{Mgsinθ}{2 M}$

a $= \frac{1}{2} gsinθ$

Now, the block on ground is moving due to tension

Hence, $T = Ma = \frac{Mgsinθ}{2}$

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Two blocks , each having a mass M, rest on frictionless floor surfaces as shown in the figure. If the pulleys are light and frictionless and M on the incline is allowed to move down, then the tension in the string will be