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Two blocks A and B are connected by a massless string as shown in figure. Force of $F = 30 N$ is applied on block (assuming no friction) $B .$ Then distance traveled by the centre of mass in $2$ second starting from rest is $x$ metres. Find the value of $x$ .

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answer is 2.

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Detailed Solution

Acceleration of the centre of mass is $a_{c m} = \frac{F}{m_{A} + m_{B}} = \frac{30}{10 + 20} = 1 m / s^{2}$

Distance travelled by the centre of mass in 2 second is $S = \frac{1}{2} a_{c m} t^{2} = \frac{1}{2} \times 1 \times 4 = 2 m$

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