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Q.

Two blocks A and B each of mass ‘ $m$ ’ are placed on a smooth horizontal surface. Forces F and 2F are applied on blocks A and B, respectively, as shown in figure. Block A does not slide on block B. Then the normal reaction acting between the two blocks is [Assume no friction between the blocks]

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a

$F$

b

$\frac{F}{\sqrt{3}}$

c

$\frac{F}{2}$

d

$3 F$

answer is D.

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Detailed Solution

Acceleration of two mass system is $a = \frac{F}{2 m}$ leftwards

$N \cos 60 - F = m a = \frac{m F}{2 m}$

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$\Rightarrow N = 3 F$

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