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Two blocks A and B, each of same mass are attached by a thin inextensible string through an ideal pulley. Initially block B is held in position as shown in figure. Now, the block B is released. Block A will slide to right and hit the pulley in time $t_{A}$ . Block B will swing and hit the surface in time $t_{B} \cdot$ Assume the surface as frictionless, then

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$t_{A} > t_{B}$

$t_{A} < t_{B}$

$t_{A} = < t_{B}$

$t_{A} = t_{B}$

answer is B.

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Detailed Solution

Horizontal displacement of both is same = l. Horizontal force on A is complete T. But horizontal force on B is not complete T. It is component of T. So, horizontal acceleration of B will be less.

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