Two blocks A and B of mass 2m and m respectively are moving on the horizontal frictionless surface with velocity V to right. If A collides with C of mass m with velocity V to right. If A collides with C of mass m compressions of the spring will be

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\sqrt{\frac{27 m}{8 K}} v$

$\sqrt{\frac{9 m}{8 K}} V$

$\sqrt{\frac{3}{2} \frac{m}{k}} v$

$\sqrt{\frac{8 m}{27 K}} \lor$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

After collision the 2m mass moves with $\frac{V}{3}$ in the forward direction.
Max KE loss = $\frac{1}{2} μ u_{r e l^{2}} = \frac{1}{2} \frac{2 m}{3} {(\frac{2 V}{3})}^{2} = \frac{4}{27} m V^{2}$
It is equal to the PE of spring at max compression. So, $\frac{1}{2} K x^{2} = \frac{4}{27} m V^{2}$

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

🔥 Start Your JEE/NEET Prep at Just ₹1999 / month - Limited Offer! Check Now!

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET