Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

Two blocks A and B of masses mA=1kg and mB=3kg are kept on table as shown in figure. The coefficient of friction between A and B is 0.2 and between B and surface of table also 0.2.  The maximum force F (in N) can be applied on B horizontally, so that the block A does not slide over the block B is 2x. The value of x is (take g=10m/s2)

Question Image

 

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

answer is 8.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Question Image

 

 

 

 

 

 

 

 

xF+0.2(3+1)X10=(3+1)2

F=8+8=16N

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon