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Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A force F applied on the upper string
produces an acceleration of 2 $m / s^{2}$ in the upward direction in both the blocks. If T and $T^{t}$ be the tensions in the two parts of the string, then

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$T = 70.8 and T^{'} = 47.2 N$

$T = 58.8 N and T^{'} = 47.2 N$

$T = 70.8 N and T^{'} = 58.8 N$

$T = 70.8 N and T^{'} = 0$

answer is A.

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Detailed Solution

FBD of mass 2 kg FBD of mass 4 kg

$T - T^{'} - 20 = 4 - - - - (i) T^{'} - 40 = 8 - - - - (ii)$

By solving (i) and (ii) $T^{'} = 47.23 N and T = 70.8 N$

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