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Q.

Two blocks are connected by a string passing over a pulley as shown. Wedge is fixed. M is sliding down with speed 12 m/s at an instant and suddenly the string breaks. The coefficient of friction between the blocks and wedge is 12 . Find the velocity (in m/s) of block M with respect to m after t = 2 seconds from the moment the string breaks.  [Take g = 10 ms2  and  32=1.2 . Assume that the length of incline is sufficiently long.]
 

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a

10

b

15

c

2.5

d

20

answer is A.

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Detailed Solution

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aM=gsin30gcos302=56=1m/s2

am=(gsin30+gcos302)=11  m/s2

As limiting friction is greater than mgsin θ , block ‘m’ will not move after  t=1211sec.

vM=121×2=10m/s

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