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Q.

Two blocks are connected over a mass less pulley as shown in the figure. The mass of block A is 10 kg and the coefficient of kinetic friction is 0.2, Block A slides down the incline at constant speed. The mass of block B in Kg

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a

3.5

b

3.3

c

3.0

d

2.5

answer is B.

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Detailed Solution

mgsin⁡θ=μmgcos⁡θ+MgM=msin⁡θ−μmcos⁡θ=m(sin⁡θ−μcos⁡θ)=10sin⁡30∘−0.2cos⁡30∘=100.5−0.2×32=5−1.732=3.268=3.3Kg

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