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Two blocks lie on each other and connected to a spring as shown in figure. What should be the mass of blocks A placed on blocks B of mass 6kg, so that the system’s period is 0.75 s Assume no slipping, what should be the minimum value of coefficient of static friction $μ_{s}$ for which block A will not slip relative to block B, if block B is displaced 50 mm from equilibrium position and released?

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$2 k g, μ_{s} = 0.4$

$4.2 k g, μ_{s} = 0.358$

$2.56 k g, μ_{s} \geq 0.358$

$2.56 k g, μ_{s} \leq 0.358$

answer is C.

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Detailed Solution

$T = 2 π \sqrt{\frac{m_{1} + m_{2}}{k}} a n d μ = \frac{A ω^{2}}{g}$

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