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Two blocks $m_{1} a n d m_{2}$ are in equilibrium. $S_{1}$ is a string and $S_{2}$ is a spring constant k. Immediately after the string $S_{1}$ is cut

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the acceleration of $m_{1}$ is $\frac{m_{2} g}{m_{1}}$

the acceleration of $m_{2}$ is $(\frac{m_{1}}{m_{1} + m_{2}}) g$

the acceleration of $m_{1}$ is $\frac{m_{2} g}{m_{1} + m_{2}}$

the acceleration of $m_{1}$ is zero

answer is C.

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Detailed Solution

Even after the string S1 is cut the tension in the spring will remain the same immediately after string is cut.

$\begin{array}{l} m_{1} a = m_{2} g \\ \Rightarrow a = \frac{m_{2} g}{m_{1}} \end{array}$

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