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Q.

Two blocks of mass M₁=20kg and M₂=12 kg are connected by a metal rod of mass 8kg.The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid point of the rod is

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a

144N

b

240N

c

96N

d

192N

answer is D.

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Detailed Solution

$\begin{array}{l} a = \frac{F}{M} = \frac{480 - (20 + 12 + 8) 10}{20 + 12 + 8} = 2 m / \sec^{2} \end{array}$

$\begin{array}{l} T = [M_{2} + \frac{m a s s o f r o d}{2}] (g + a) = (12 + 4) (12) = 192 N \end{array}$

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Two blocks of mass M1=20kg and M2=12 kg are connected by a metal rod of mass 8kg.The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid point of the rod is