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Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m/s to the heavier block in the direction of the lighter block. The velocity of the centre of mass is

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30 m/s

20 m/s

5 m/s

10 m/s

answer is C.

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Detailed Solution

$v_{C M} = \frac{10 (14) + 4 (0)}{10 + 14} = 10 m / s$

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