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Two blocks of masses 2 kg and 5 kg are at rest on ground. The masses are connected by a string passing over a frictionless pulley which is under the influence of a constant upward force F = 50 N. Find the acceleration of 5 kg and 2 kg masses

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$2 .5 {m/s}^{2}, 5 {m/s}^{2}$

$0, 2 .5 {m/s}^{2}$

$2 .5 {m/s}^{2}, 0$

$5 {m/s}^{2}, 2 .5 {m/s}^{2}$

answer is A.

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Detailed Solution

$25 - 2 \times 10 = 2 a 5 = 2 a \Rightarrow a = \frac{5}{2} = 2 .5 {ms}^{- 2} \Rightarrow a_{2 kg} = 2 .5 {ms}^{- 2}$

From the figure,
Upward force on block <weight of the block
So that 5kg block does not move
$a_{5} = 0 {ms}^{- 2}$

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