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Two blocks of masses 3kg and 2kg are placed beside each other in contact with each other on a rough horizontal surface. A horizontal force of 20N is applied on 3kg. The coefficient of friction between blocks and the surface is 0.1 and g = 10ms^-2. The force of contact between the two blocks is

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a

6 N

b

8 N

c

10 N

d

12 N

answer is B.

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$\begin{array}{l} F - f_{1} - f_{} = m_{1} a; f - f_{2} = m_{2} a \\ \Rightarrow \frac{F - f_{1} - f}{f - f_{2}} = \frac{m_{1}}{m_{2}} \\ \frac{20 - 0.1 \times 3 \times 10 - f}{f - 0.1 \times 2 \times 10} = \frac{3}{2} \\ 2 (20 - 3 - f) = 3 (f - 2) \\ 40 - 6 - 2 f = 3 f - 6; 5 f = 40 \\ f = 8 N \end{array}$

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