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Q.

Two blocks of masses $3 m$ and $2 m$ are in contact on a smooth table. A force P is first applied horizontally on block of mass $3 m$ and then on mass $2 m$ . The contact force between the two blocks in the two cases are in the ratio.

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a

$1 : 2$

b

$2 : 3$

c

$3 : 2$

d

$5 : 3$

answer is B.

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Detailed Solution

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On 3m: $P - N_{1} = 3 m a$

$\Rightarrow P - N_{1} = 3 m (\frac{P}{5 m})$

$\Rightarrow N_{1} = \frac{2 P}{5}$
On 2m: $P - N_{2} = 2 m a$

$\Rightarrow P - N_{2} = 2 m (\frac{P}{5 m})$

$\Rightarrow N_{2} = \frac{3 P}{5}$

Ratio, $\frac{N_{1}}{N_{2}} = \frac{2}{3}$

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Two blocks of masses 3m and 2m are in contact on a smooth table. A force P is first applied horizontally on block of mass 3m and then on mass 2m . The contact force between the two blocks in the two cases are in the ratio.