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Two blocks of masses 5kg and 2kg are placed on a friction less surface and connected by a spring an external kick gives a velocity of 14 m/s to the heavier block in the direction of lighter one calculate the velocity of centre of mass?

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14 m/s

7 m/s

10 m/s

“O” m/s

answer is C.

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Detailed Solution

$v_{c m} = \frac{m_{1} v_{1} + m_{2} v_{2}}{m_{1} + m_{2}} = \frac{5 \times 14 + 2 \times 0}{5 + 2} = \frac{5 \times 14}{7} = 5 \times 2 = 10 m / s$

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