Two blocks of masses m and 2m are placed one over the other as shown in figure. The coefficient of friction between m and 2m is μ and between 2m and ground is μ3. If a horizontal force F is applied on upper block and T is tension developed in string, then choose the incorrect alternative.

f1 = maximum value of friction between m and 2m = μmgf2 = maximum value of friction between 2m and ground = μ33mg = μmgNow, let us free body diagram of m and 2m in all four cases.Tension will be zero in all four cases.

Two blocks of masses m and 2m are placed one over the other as shown in figure. The coefficient of friction between m and 2m is μ and between 2m and ground is μ3. If a horizontal force F is applied on upper block and T is tension developed in string, then choose the incorrect alternative.

f1 = maximum value of friction between m and 2m = μmgf2 = maximum value of friction between 2m and ground = μ33mg = μmgNow, let us free body diagram of m and 2m in all four cases.Tension will be zero in all four cases.

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Two blocks of masses m and 2m are placed one over the other as shown in figure. The coefficient of friction between m and 2m is μ and between 2m and ground is $\frac{μ}{3}$ . If a horizontal force F is applied on upper block and T is tension developed in string, then choose the incorrect alternative.

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If F = $\frac{μ}{3}$ mg, T = 0

If F = μmg, T = 0

If F = 2μmg, T = $\frac{μ m g}{3}$

If F = 3μmg, T = 0

answer is C.

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Detailed Solution

f₁= maximum value of friction between m and 2m = μmg
f₂ = maximum value of friction between 2m and ground = $\frac{μ}{3} (3 m) g$ = μmg
Now, let us free body diagram of m and 2m in all four cases.