Two blocks of masses M and m are connected to each other by a massless string and spring of force constant k as shown in the figure. The spring passes over a frictionless pulley connected rigidly to the edge of a stationary block A. The coefficient of friction between block M and the plane horizontal surface of A is $μ$ . The block M slides over the horizontal top surface of A and block m slides vertically downwards with the same speed. The mass M is equal to

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$\frac{m}{μ}$

$\frac{2 m}{μ}$

$m μ$

$μ m g$

answer is A.

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Detailed Solution

When the system of two blocks of masses M and m is either at rest or moving with the same speed, no net force acts on them.

In this equilibrium state,

$T = μ R = μ M g and T = m g$

$∴ μ M g = m g \Rightarrow M = \frac{m}{μ}$

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