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Two blocks of masses m₁ and m₂ are connected through a massless inextensible string. A block of mass m₁ is placed at the fixed rigid inclined surface while the block of mass m₂ hanging at the other end of the string, which is passing through a fixed massless frictionless pulley shown in the figure. The coefficient of static friction between the block and the inclined plane is 0.8. The system of masses m₁ and m₂ is released from rest. (g = 10 ms^-2)

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None of these

The tension in the string is 20 N after releasing the system.

The magnitude of contact force by the inclined surface on the, block m₁ is $20 \sqrt{3} N$ .

The contact force by the inclined surface on the block is along normal to the inclined surface.

answer is A, B, C.

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Detailed Solution

Here $m_{1} gsin 30^{\circ} = m_{2} g = 20 N$ , so there is no tendency of motion in any direction.

Hence, there is no friction on m₁. Contact force will be only normal force.

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