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Two blocks of masses $m_{1}$ and $m_{2}$ are placed in contact on a horizontal frictionless surface as shown in figure. A force F is applied to mass $m_{1}$ as shown.

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The acceleration of mass $m_{2} i s F / m_{2}$

The force exerted on mass $m_{2} i s \frac{m_{2} F}{(m_{1} + m_{2})}$

The force exerted on mass $m_{2} i s F$

The acceleration of mass $m_{1} i s \frac{F}{(m_{1} + m_{2})}$

answer is B, D.

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Detailed Solution

The acceleration of both the masses is the same and is given by

$a = \frac{net force}{total mass} = \frac{F}{(m_{1} {+m}_{2})}$

Force on mass $m_{2} {= m}_{2} a$

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