Q.

Two blocks of masses m1=1kg and m2=2kg are connected by a non-deformed light spring. They are lying on a rough horizontal surface. The coefficient of friction between the blocks and the surface is 0.4 . What minimum constant force F has to be applied in horizontal direction to the block of mass m1  in order to shift the other block (g=10ms2)

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a

10 N

b

15 N

c

8 N

d

25 N

answer is A.

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Detailed Solution

According to work energy theorem

Fxμm1gx12kx2=0

Fxμm1gx12μm2gx=0

F=μ(m1+m22)g=0.4(1+22)10=8N

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