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Two blocks of masses $10 kg$ and $30 kg$ are placed on the same straight line with coordinates $(0, 0) cm$ and $(x, 0) cm$ respectively. The block of $10 kg$ is moved on the same line through a distance of $6 cm$ towards the other block. The distance through which the block of $30 kg$ must be moved to keep the position of centre of mass of the system unchanged is :

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4 cm towards the 10 kg block

2 cm away from the 10 kg block

2 cm towards the 10 kg block

4 cm away from the 10 kg block

answer is C.

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Detailed Solution

$Δ x_{G} = \frac{m_{1} Δ x_{1} + m_{2} Δ x_{2}}{m_{1} + m_{2}} 0 = \frac{10 \times 6 + 30 (Δ x_{2})}{40} Δ x_{2} = - 2 c m$
Block of mass 30 kg will to move towards 10 kg.

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