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Two bodies A and B started from rest and moving in the same direction with acceleration $a_{A} = 4 m / s^{2}$ and $a_{B} = 1 m / s^{2}$ . If the initial separation between them is 60m. After what time they will meet ?

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$\sqrt{40} s$

$\sqrt{20} s$

$\sqrt{30} s$

$\sqrt{10} s$

answer is A.

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Detailed Solution

$\begin{array}{rcl} S & = & \frac{1}{2} a_{r} t^{2} \\ t & = & \sqrt{\frac{2 s}{a_{r}}} = \sqrt{\frac{2 \times 60}{3}} = \sqrt{40} s \end{array}$

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