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Q.

Two bodies of different masses m_a and m_b are dropped from two different heights, viz; a and b. The ratio of time taken by the two to drop through these distances, is:

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a

$\sqrt{a} : \sqrt{b}$

b

a: b

c

a²:b²

d

m_a/m_b: b/a

answer is C.

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Detailed Solution

$a = \frac{1}{2} {gt}_{1}^{2}$ , $b = \frac{1}{2} {gt}_{2}^{2}$

$\Rightarrow \frac{t_{1}}{t_{2}} = \sqrt{\frac{a}{b}}$

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