Two bodies of mass 10 kg each are separated by 1 metre. the force of attraction between them is

Given:

$\text{m}=10\text{kg}$ 

$\text{r}=\text{1m}$

$\text{G}=\text{6}\text{.67}\times {\text{10}}^{-11}{\text{Nm}}^{\text{2}}{\text{kg}}^{-2}$

Solution:

$\text{F}=\text{G}\frac{{\text{m}}_{\text{1}}{\text{m}}_{\text{2}}}{{\text{r}}^{\text{2}}}$

$\mathrm{F}=\frac{6.67\times {10}^{-11}\times 100}{{\left(1\right)}^2}$

$\text{F}=6.67\times {10}^{-9}\text{N}$
 

Hence option A is the correct answer.