Two bodies of mass 10² kg and10³ kg are lying 1 m apart. The gravitational potential at the mid-point of the line joining them is -

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-1.47 Joule/kg

$- 1 .47 \times 10^{- 7} Joule / kg$

$1 .47 Joule / kg$

answer is C.

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Detailed Solution

$V_{g} = V_{g 1} + V_{g 2} = - \frac{{Gm}_{1}}{r_{1}} - \frac{{Gm}_{2}}{r_{2}} = - 6 .67 \times 10^{- 11} [\frac{10^{2}}{0 .5} + \frac{10^{3}}{0 .5}] = - 1 .47 \times 10^{- 7} Joule / kg$

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