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Q.

Two bodies of mass 4 kg and 6kg are tied to the ends of a maasless string. The string passes over a pulley which is frictionless (see figure). The accleration of the system in terms of acceleration due to gravity (g) is :

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a

g / 2

b

g / 5

c

g / 10

d

g

answer is B.

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Detailed Solution

$a = \frac{(6 - 4) g}{10} = \frac{g}{5}$

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Two bodies of mass 4 kg and 6kg are tied to the ends of a maasless string. The string passes over a pulley which is frictionless (see figure). The accleration of the system in terms of acceleration due to gravity (g) is :