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Two bodies of masses 1 kg and 4 kg are connected to a vertical spring, as shown in the figure. The smaller mass executes simple harmonic motion of angular frequency 25 rad/s, and amplitude 1.6 cm while the bigger mass remains stationary on the ground. The maximum force exerted by the system on the floor is (take g = 10 ms^-2).

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10 N

60 N

20 N

40 N

answer is B.

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Detailed Solution

$\begin{array}{l} F_{max} = m_{2} g + m_{1} (g + a_{max}) = m_{2} g + m_{1} (g + {Aω}^{2}) \\ = 4 \times 10 + 1 (10 + 1 .6 \times 10^{- 2} \times 25 \times 25) \\ = 40 + (10 + 10) = 40 + 20 = 60 N \end{array}$

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