Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Two bodies of masses 15gm and 25gm are connected by means of a string of length 40cm and mass 10gm. The string is made to pass over a smooth massless pulley. Initially the two bodies are kept at the same level and released. By the time the heavier mass descends by 10cm, the acceleration of the system,

Question Image

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

Increases by a factor 1.5

b

Decreases

c

Remains constant 1

d

Increases by a factor 3

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Question Image

Given mstring=10gm

lstring=40cm

Initially when two are at same level for 20 cm length mass is 5 gm

Case 1 : acceleration, a=[302030+20]g

a=1050g

a=g5=2g10ms2

Case 2 : when larger mass descends by 10 cm

a1=[32.517.550]g

[for 10 cm mass = 2]

a1=3g/10

Acceleration increases by a factora1a=32=1.5

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring