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Two bodies of masses 16 kg and 4 kg at rest to acted upon by same force. The ratio of times required to attain the same speed is,

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1 : 1

4 : 1

1 : 4

1 : 2

answer is B.

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Detailed Solution

$F = \frac{m (v - u)}{t} \Rightarrow m V = F t \Rightarrow m \propto t \Rightarrow \frac{m_{1}}{m_{2}} = \frac{t_{1}}{t_{2}}$

$\frac{t_{1}}{t_{2}} = \frac{16}{4} = \frac{4}{1}$

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