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Two bodies of masses 4 kg and 6 kg connected by means of a light string are lying on a smooth horizontal surface. A horizontal pulling force is applied on the lighter body. Two seconds later the string connecting the two masses is cut. After two more seconds if the velocity of the heavier mass is $2 m s^{- 1}$ , the force initially applied is

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20N

10N

25N

40N

answer is A.

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Detailed Solution

The tension in the string P accelerate the 6 kg block when the string between the blocks breaks .

P= 6 a where a= $\frac{F}{4 + 6}$

Velocity of 6Kg block after 2 sec is v=u $+$ at $\Rightarrow$ 2 =0 $+$ $\frac{F}{10} \times 2$ $\Rightarrow F = 10 N$

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