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Q.

Two bodies of masses 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a pulley which is frictionless (see figure). The acceleration of the system in terms of acceleration due to gravity g is

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a

g/2

b

g/5

c

g/10

d

g

answer is B.

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Detailed Solution

Given,  m1=4 kg,m2=6 kg and a=?

The free body diagram of given system is shown below

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The balancing equations for given system are

          T-m1g=m1a                                     …(i)

and   m2g-T=m2a                                      … (ii)

Adding Eqs. (i) and (ii), we get

m2g-m1g=m1a+m2a

  a=m2-m1m1+m2·g=6-44+6×g=g5

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