Q.

Two bodies of masses m1 and m2 moving on the same direction with velociities u1 and u2 collide. The velocities after collision are V1 and V2. If each sphere loses the same amount of kinetic energy, then

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a

u1 + u2 + V1 + V2 = 0

b

u1 – u2 + V1 + V2 = 0

c

u1+ u2 – V1 – V2 = 0

d

u1 + u2 + V1 – V2 = 0

answer is C.

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Detailed Solution

Explanation

For body 1:

ΔKE1 = ½m1(u12 - V12)

For body 2:

ΔKE2 = 1/2m2(u22 - V22)

Since both bodies lose the same amount of kinetic energy: 
m1(u12 - V12) = m2(u22 - V22)

The total momentum before and after the collision is conserved: m1u1 + m2u2 = m1V1 + m2V2

From the energy equation:

u12 - V12 = (m2/m1)(u22 - V22)

Using the identity a2 - b2 = (a + b)(a - b):

(u1 + V1)(u1 - V1) = (m2/m1)(u2 + V2)(u2 - V2)

From the momentum conservation equation, divide throughout by m1 + m2:

u1 - V1 = (m2/m1)(V2 - u2)

Substituting back into the energy equation and simplifying, we find:

u1 + u2 = V1 + V2

Final Answer

u1 + u2 - V1 - V2 = 0

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