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Two bodies performing SHM have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is

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$2 π / 3$

$π$

$π / 3$

None

answer is A.

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Detailed Solution

Displacement from mean position

$= A - (\frac{2 - \sqrt{3}}{2}) A = \frac{\sqrt{3}}{2} A$

So phase of the particle which is going to wards $+ x is ϕ_{1} = \frac{π}{3}$

phase difference $= \frac{5 π}{3} - \frac{π}{3}$

$= \frac{4 π}{3} or (2 π - \frac{4 π}{3})$

$= \frac{4 π}{3} or \frac{2 π}{3}$

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