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Two brands of chocolates are available in packs of 24 and 15 respectively. If I need to buy an equal number of chocolates of both kinds, what is the least number of boxes of each kind I would need to buy?

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An Intiative by Sri Chaitanya

8 and 4

6 and 5

4 and 6

5 and 8

answer is A.

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Detailed Solution

It is given that two brands of chocolates are available in packs of 24 and 15 respectively.
Calculator of LCM of 24 and 15 as follows:

24 = 2 \times 2 \times 2 \times 3

15 = 3 \times 5

\Rightarrow LCM (24, 15) = 120

The number of boxes of a pack of 24

= \frac{120}{24}

\Rightarrow

The number of boxes of a pack of 24

= 5

Similarly, the number of boxes of a pack of 15

= \frac{120}{15}

\Rightarrow

The number of boxes of a pack of 15

= 8

Hence, 5 of the first kind and 8 of the second kind are required.
Hence, option 1 is correct.

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