Two bulbs 25 watt- 100 volt (bulb E) and 100 watt- 200 volt (bulb F) are connected in the circuit as shown in figure. Choose the correct answer (s).

Heat lost per second in the circuit   $=\frac{V^2}{R_{\text{eq }}}=\frac{4\times {10}^4}{500}$  $=80J$
Ratio of heat produced in bulbs  ${\text{I}}_1^2{\text{R}}_1:{\text{I}}_2^2{\text{R}}_2=\frac{4{\text{I}}^2\text{R}}{{\text{I}}^2\text{R}}=4:1$ 

Ratio of heat produced in branch  AB  to  CD
$=\frac{{\text{V}}_1^2/{\text{R}}_1}{{\text{ V}}_2^2/{\text{R}}_2}=\frac{{\text{R}}_2}{{\text{R}}_1}=2:1({\text{as\hspace{0.17em}\hspace{0.17em}V}}_1={\text{V}}_2)$
Current drawn from the cell  $=\frac{\text{V}}{{\text{R}}_{\text{eq}}}=0.4A$