Two bulbs 25W, 100V (upper bulb in figure) and 100W, 200V (lower bulb in figure) are connected in the circuit as shown in figure. Choose the correct answer

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Heat lost per second in the circuit will be 80J

Ratio of heat produced per second in bulbs will be 1: 1

Ratio of heat produced in branch AB to branch CD will be 1:2

Current drawn from the cell is 0.2 A

answer is A.

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Detailed Solution

Total resistance $= \frac{500}{3} + \frac{(100 + \frac{100^{2}}{25}) (600 + \frac{200^{2}}{100})}{100 + \frac{100^{2}}{25} + 600 + \frac{200^{2}}{100}} = 500$ ohm
Required heat $= \frac{200^{2}}{500} = 80 J$

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