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Q.

Two bulbs A and B contain 16 g O₂and 16 g O₃, respectively. Which of the statements are true?

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a

Both bulbs contain same number of atoms.

b

Bulb A contains N_A/2 molecules while bulb B contains N_A/3 molecule. (N_A=Avogadro's number).

c

Both bulbs contain different number of atoms.

d

Both bulbs contain same number of molecules

answer is A, D.

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Detailed Solution

1. Number of of O₂ atom = $\frac{16}{32} \times 2 \times N_{A} = 1 \times N_{A}$

2.Nurnber of of O₃ atoms = $\frac{16}{48} \times 3 \times N_{A} = 1 \times N_{A}$

3. i. Number of O₂ molecules = $\frac{16}{32} \times N_{A} = \frac{1}{2} N_{A}$

ii. Number of O₂ molecules = $\frac{16}{48} \times N_{A} = \frac{1}{3} \times N_{A}$

(4) is correct.

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