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Q.

Two buses P and Q start from a point at the same time and move in a straight line and their positions are represented by XP(t)=αt+βt2 and XQ(t)=ft-t2. At what time, both the buses have same velocity?

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a

αf1+β

b

α+f2(β1)

c

α+f2(1+β)

d

fα2(1+β)

answer is D.

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Detailed Solution

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 Xp(t)=αt+βt2          XQ=ftt2 VP(t)=α+2βt          VQ=f2t VP=VQ α+2βt=f2t t=fα2β+2

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