Two capacitors of capacitance 1 μF and 2 μF are separately charged by a common battery. The two capacitors start discharging through equal resistances separately at t = 0.

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The currents in two discharging circuits are equal at all times

The currents in the two discharging circuits at t = 0 are equal but not zero

The current in each of the two discharging circuit is zero at t = 0

Capacitor of 1 μF capacity loses 50% of its charge earlier than capacitor of capacity 2 μF

answer is B, D.

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Detailed Solution

I = V/R at t = 0. They are same.

$i = I_{0} e^{- t / τ}$ for both circuits I₀ is same but $τ$ is different.

So, i will be different at the same 't'.

The time constant $τ$ is less for 1µF

$∴$ It will discharge sooner.

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