Two capacitors of capacities (3±0.09)μF and (6±0.09)μF are connected in parallel. Their equivalent capacity is

C1=(3±0.09)μF;C2=(6±0.09)μFCp=C1+C2=3+6=9ΔCp=ΔC1+ΔC2=0.09+0.09=0.18(9±0.18)μF

Two capacitors of capacities (3±0.09)μF and (6±0.09)μF are connected in parallel. Their equivalent capacity is

C1=(3±0.09)μF;C2=(6±0.09)μFCp=C1+C2=3+6=9ΔCp=ΔC1+ΔC2=0.09+0.09=0.18(9±0.18)μF

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Two capacitors of capacities $(3 \pm 0.09) μ F$ and $(6 \pm 0.09) μ F$ are connected in parallel. Their equivalent capacity is

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$(2 \pm 0.13) μ F$

$(9 \pm 0.18) μ F$

$(9 \pm 0.09) μ F$

$(2 \pm 0.09) μ F$

answer is B.

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$\begin{array}{l} C_{1} = (3 \pm 0.09) μF; C_{2} = (6 \pm 0.09) μF \\ C_{p} = C_{1} + C_{2} = 3 + 6 = 9 \\ ΔCp = {ΔC}_{1} + {ΔC}_{2} = 0.09 + 0.09 = 0.18 \\ (9 \pm 0.18) μF \end{array}$

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Two capacitors of capacities (3±0.09)μF and (6±0.09)μF are connected in parallel. Their equivalent capacity is

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Two capacitors of capacities $(3 \pm 0.09) μ F$ and $(6 \pm 0.09) μ F$ are connected in parallel. Their equivalent capacity is