Two capacitors of capacity 4µF and 6µF are connected in series and a battery is connected to the combination. The energy stored is E₁. If they are connected in parallel and if the same battery is connected to this combination the energy stored is E₂. The ratio E₁:E₂ is

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9 : 14

7 : 12

4 : 9

6 : 25

answer is C.

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Detailed Solution

Case I $E_{1} = \frac{1}{2} \times \frac{4 \times 6}{4 + 6} V^{2}$
Case II $E_{2} = \frac{1}{2} \times 10 \times V^{2}; \frac{E_{1}}{E_{2}} = \frac{24}{100} = \frac{6}{25}$

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