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Q.

Two capacitors of $10 μ F and 20 μ F$ are connected in series with a 30V battery. The charge on the capacitors will be, respectively

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a

$200 μ C, 200 μ C$

b

$200 μ C, 100 μ C$

c

$100 μ C, 100 μ C$

d

$100 μ C, 200 μ C$

answer is D.

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Detailed Solution

In series combination of capacitor charge on each capacitor is same $Q_{1} = Q_{2} = Q = C_{e q} V$

$\Rightarrow C_{e q} V = (\frac{10 \times 20}{10 + 20}) \times 30 = \frac{200}{30} \times 30 = 200 μ C$

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