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Q.

Two capacitors with capacitance 2C and C are joined in parallel and charged up to potential V. The battery is removed and the capacitor of capacity C is filled completely with a medium of dielectric constant K. The potential difference across the capacitors equals:

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a

VK

b

3VK

c

VK+2

d

3VK+2

answer is A.

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Detailed Solution

q1=2CV, q2=CV

Now condenser of capacity C is filled with dielectric K, therefore C2 = KC

As charge is conserved

∴   q1+q2=C2+2CV

⇒V′=3CV(K+2)C=3VK+2

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