Two cards are drawn without replacement from a well-shuffled pack. The probability that one of them is an ace of heart, is

There are two conditions arise.
(i) When first is an ace of heart and second one is non-ace of heart, the probability $=\frac{1}{52}\times \frac{51}{51}=\frac{1}{52}$
(ii) When first is non-ace of heart and second one is an ace of heart, the probability $=\frac{51}{52}\times \frac{1}{51}=\frac{1}{52}$
.'. Required probability $=\frac{1}{52}+\frac{1}{52}=\frac{1}{26}$