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Two cars A and B cross a point P with velocities 10m/s and 15 m/s. after that they move with different uniform accelerations and the car A overtakes B with a speed of 25 m/s. Their accelerations are in the ratio

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3 : 1

2 : 1

3 : 2

4 : 3

answer is A.

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Detailed Solution

They have travelled for same distance for same time.
So, $s = \frac{(v_{1} + u_{1})}{2} t = (\frac{v_{2} + u_{2}}{2}) t$

$(10 + 25) = 15 + u_{2}$

$u_{2} = 20 m / s$

$\begin{array}{l} a_{1} = \frac{25^{2} - 10^{2}}{2 S} \\ a_{2} = \frac{20^{2} - 15^{2}}{2 S} a_{1} : a_{2} = 3 : 1 \end{array}$

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