Q.

Two cars A and B initially at rest are moving in same direction with acceleration a1 and a2 respectively. After a certain time, they achieve velocities v1 and v2 respectively and separated are by a distance of 50 m. If (a1  a2) = 4m/s2, then the quantity (v1 – v2) will be

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a

12 m/s

b

20 m/s

c

40 m/s

d

24 m/s

answer is B.

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Detailed Solution

Given relative acceleration (a1-a2) = 4m/s2

Displacement = 50m

Using v2 - u2 = 2as

v2 = 2(4)(50)

v = 20m/s

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