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Two cars moving in opposite directions approach each other with speed of 22 m/s and 16.5 m/s respectively. The driver of the first car blows a horn having a frequency 400 Hz. The frequency heard by the driver of the second car is [velocity of sound 340 m/s]:

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350 Hz

448 Hz

361 Hz

411 Hz

answer is A.

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Detailed Solution

$n^{1} = [\frac{v + v_{0}}{v - v_{s}}] n = [\frac{340 + 16.5}{340 - 22}] 400 = 448.4 Hz$

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